8a^2-45a+25=0

Solution for 8a^2-45a+25=0 equation:

8a^2-45a+25=0

a = 8; b = -45; c = +25;
Δ = b2-4ac
Δ = -452-4·8·25
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-35}{2*8}=\frac{10}{16}
=5/8
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+35}{2*8}=\frac{80}{16}
=5
$